Demo

Inline Syntax

Use $tex expression$.

Euler's identity $e^{i\pi}+1=0$ is a beautiful formula in $\mathbb{R}^2$.

Euler's identity $e^{i\pi }+1=0$ is a beautiful formula in ${\mathbb{R}}^2$.

Block Syntax

Use $$tex expression$$.

$$
\frac {\partial^r} {\partial \omega^r} \left(\frac {y^{\omega}} {\omega}\right)
= \left(\frac {y^{\omega}} {\omega}\right) \left\{(\log y)^r + \sum_{i=1}^r \frac {(-1)^ Ir \cdots (r-i+1) (\log y)^{ri}} {\omega^i} \right\}
$$

$$\frac{{\partial }^r}{\partial {\omega }^r}\left(\frac{y^{\omega }}{\omega }\right)=\left(\frac{y^{\omega }}{\omega }\right)\{(\log y{)}^r+\sum _{i=1}^r\frac{(-1{)}^{I}r\cdots (r-i+1)(\log y{)}^{ri}}{{\omega }^i}\}$$

mhchem

need mhchem extension, see mhchem extension

$$
\ce{Zn^2+  <=>[+ 2OH-][+ 2H+]  $\underset{\text{amphoteres Hydroxid}}{\ce{Zn(OH)2 v}}$  <=>[+ 2OH-][+ 2H+]  $\underset{\text{Hydroxozikat}}{\ce{[Zn(OH)4]^2-}}$}
$$

$$\mathrm{Zn}{\phantom{A}}^{2+}\underset{+2\mathrm{H}{\phantom{A}}^{+}}{\stackrel{+2\mathrm{OH}{\phantom{A}}^{-}}{\stackrel{-\rightharpoonup }{\leftharpoondown -}}}\underset{\text{amphoteres Hydroxid}}{\mathrm{Zn}(\mathrm{OH}){\phantom{A}}_2\downarrow }\underset{+2\mathrm{H}{\phantom{A}}^{+}}{\stackrel{+2\mathrm{OH}{\phantom{A}}^{-}}{\stackrel{-\rightharpoonup }{\leftharpoondown -}}}\underset{\text{Hydroxozikat}}{[\mathrm{Zn}(\mathrm{OH}){\phantom{A}}_4]{\phantom{A}}^{2-}}$$